CBSE Class 10 Mathematics Statistics Worksheet Set A

Read and download free pdf of CBSE Class 10 Mathematics Statistics Worksheet Set A. Students and teachers of Class 10 Statistics can get free printable Worksheets for Class 10 Statistics in PDF format prepared as per the latest syllabus and examination pattern in your schools. Standard 10 students should practice questions and answers given here for Statistics in Grade 10 which will help them to improve your knowledge of all important chapters and its topics. Students should also download free pdf of Class 10 Statistics Worksheets prepared as per the latest NCERT, CBSE, KVS books and syllabus issued this academic year and solve important problems provided here with solutions on daily basis to get more score in school exams and tests

 

Statistics Worksheet for Class 10

Class 10 Statistics students should refer to the following printable worksheet in Pdf in standard 10. This test paper with questions and answers for Grade 10 Statistics will be very useful for exams and help you to score good marks

Class 10 Statistics Worksheet Pdf

 Statistics

Q.- Given below are the ages of 25 students of class IX in a school. Prepare a discrete frequency distribution. 

15, 16, 16, 14, 17, 17, 16, 15, 15, 16, 16, 17, 15, 16, 16, 14, 16, 15, 14, 15, 16, 16, 15, 14, 15.

 Sol. Frequency distribution of ages of 25 students

Q.- Form a discrete frequency distribution from the following scores:- 

Sol. 15, 18, 16, 20, 25, 24, 25, 20, 16, 15, 18, 18, 16, 24, 15, 20, 28, 30, 27, 16, 24, 25, 20, 18, 28, 27, 25, 24, 24, 18, 18, 25, 20, 16, 15, 20, 27, 28, 29, 16.

Q.- The water tax bills (in rupees) of 30 houses in a locality are given below. Construct a grouped frequency distribution with class size of 10.

30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88,40, 14, 20, 15, 35, 44, 66, 75, 84, 95, 96, 102,110, 88, 74, 112, 14, 34, 44.

Sol. Here the maximum and minimum values of the variate are 112 and 14 respectively.

∴Range = 112 – 14 = 98.

It is given that the class size is 10, and

Range/Class size = 98/10=9.8

So, we shoule have 10 classes each of size 10.

The minimum and maximum values of the variate are 14 and 112 respectively. So we have to make the classes in such a way that first class includes the minimum value and the last class includes the maximum value. If we take the first class as 14-24 it includes the minimum value 14. If the last class is taken as 104-114, then it includes the maximum value 112. Here, we form classes by exclusive method. In the class 14-24, 14 is included but 24 is excluded. Similarly, in other classes, the lower limit is included and the upper limit is excluded.

In the view of above discussion, we construct the frequency distribution table as follows:

Q.- The marks obtained by 40 students of class IX in an examination are given below :

18, 8, 12, 6, 8, 16, 12, 5, 23, 2,16, 23, 2, 10, 20, 12, 9, 7, 6, 5, 3, 5, 13, 21, 13, 15, 20, 24,1, 7, 21, 16, 13, 18, 23, 7, 3, 18, 17, 16. 

Present the data in the form of a frequency distribution using the same class size, one such class being 15-20 (where 20 is not included)

 

Sol. The minimum and maximum marks in the given raw data are 0 and 24 respectively. It is given that 15-20 is one of the class intervals and the class size is same. So, the classes of

equal size are

0-5, 5-10, 10-15, 15-20 and 20-25

Thus, the frequency distribution is as given under :

 

Q.- The class marks of a distribution are :

47, 52, 57, 62, 67, 72, 77, 82, 87, 92, 97, 102

Determine the class size, the class limits and the true class limits.

 

Sol. Here the class marks are uniformly spaced.

So, the class size is the difference between any two consecutive class marks

∴ Class size = 52 – 47 = 5

We know that, if a is the class mark of a class interval and h is its class size, then the lower and upper limits of the class interval are 

a –h/2 and a +h/2 respectively. 

∴ Lower limit of first class interval 

= 47 – 5/2 = 44.5 

And, upper limit of first class interval 

= 47 + 5/2 = 49.5 

So, first class interval is 44.5 – 49.5 

Similarly, we obtain the other class limits as given under :

Since the classes are exclusive (continuous) so the true class limits are same as the class limits.

 

Q.- The class marks of a distribution are 26, 31, 36, 41, 46, 51, 56, 61, 66, 71. Find the true class limits.

 

Sol. Here the class marks are uniformly spaced.

So, the class size is the difference between any two consecutive class marks.

∴ Class size = 31 – 26 = 5.

If a is the class mark of a class interval of size h, then the lower and upper limits of the class interval are a – h/2 and a + h/2 respectively.

Here h = 5

∴ Lower limit of first class interval

= 26 – 5/2 = 23.5

∴ First class interval is 23.5 – 28.5.

Thus, the class intervals are:

23.5 – 28.5, 28.5 – 33.5, 33.5 – 38.5,38.5 – 43.5,43.5 – 48.5, 48.5 – 53.5 

Since the classs are formed by exclusive method. Therefore, these limits are true class limits.

 

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