The correct answer is (4) 50 metres
Solution
Let the length of train be x km
Let the speed of the train be y km/hr
2 kmph = (2 x 5/18) m/sec = 5/9 m/sec.
4 kmph = (4 x 5/18) m/sec = 10/9 m/sec.
According to the given condition
x/(y-2) = 9/(60*60)
x/(y-4) = 10/(60*60)
On combining both the equations we get
9y – 3600x = 18
and 10y – 3600x = 40
y-400x = 2
and y – 360x = 4
Therefore
40x = 2
x = (2/40 *1000)m
= 50 metres
Tags:
Maths