9303753286127016 Factorise :

Factorise :

byBalkishan Agrawal -June 20, 2022

0

Question : Factorise :

$8 x ^{3} - \frac{1}{2 7 y ^{3}}$

$8 x^{3} - \frac{1}{2 7 y ^{3}}$

Given : $8 x^{3} - \frac{1}{2 7 y ^{3}}$

According to the equation,
$a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$

So we get,
$8 x^{3} - \frac{1}{2 7 y ^{3}}$ $= (2 x)^{3} - (\frac{1}{3 y})^{3}$

Based on the formula,

$= (2 x - \frac{1}{3 y}) ((2 x)^{2} + (2 x) (\frac{1}{3 y}) + (\frac{1}{3 y})^{2})$

$8 x^{3} - \frac{1}{2 7 y ^{3}}$ $= (2 x - \frac{1}{3 y}) (4 x^{2} + \frac{2 x}{3 y} + \frac{1}{9 y ^{2}})$

Tags: Maths

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