Range R of the projectile R = 3km
Angle of projection, =30o
Acceleration due to gravity, g = 9.8m/s2
The horizontal range for the projection velocity, u0, is given by the relation:
R = uo2Sin2θ/g
3 = uo2Sin600/g
uo2/ g = 2√3 …….(i)
The maximum range (Rmax) is achieved by the bullet when it is fired at an angle of 45 with the horizontal, that is, Rmax = uo2/ g ….(ii)
On comparing equations (i) and (ii), we get:
Rmax = 2 × 1.732 = 3.46 km
Hence, the bullet will not hit a target 5 km away.
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Physics