9303753286127016 A conducting rod of length l is hinged at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field B in horizontal direction. The rod is released from the position. What is the potential difference between the two ends of the rod is proportional to?

A conducting rod of length l is hinged at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field B in horizontal direction. The rod is released from the position. What is the potential difference between the two ends of the rod is proportional to?

byBalkishan Agrawal -
0

 The gravitational potential decreases to increase the kinetic energy of the rod. The equation can be written as,

mg 1/2sinθ = 1/2Iω2 = 1/2(ml2/3)ω2

⟹ ω=√3g/lsinθ

Hence the magnetic field and the direction of velocity of rods is perpendicular. 

Total potential difference developed across the ends =

B(xω)dx 

=Bl2/2√ 3g/lsinθ ∝ l3/2√sinθ.

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Balkishan Agrawal

At the helm of GMS Learning is Principal Balkishan Agrawal, a dedicated and experienced educationist. Under his able guidance, our school has flourished academically and has achieved remarkable milestones in various fields. Principal Agrawal’s vision for the school is centered on providing a nurturing environment where every student can thrive, learn, and grow.

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