Given,
ABCD is an isosceles trapezium.
AB || CD
AB = 20 cm
CD = 10 cm
Length of each leg of trapezium = 13 cm
By the formula, the area of trapezium is:
Area of trapezium = (a+b)h/2
where a and b are parallel sides and h is the height of the trapezium.
Height of triangle, h2 = 132 – 52
h2 = 144
h = 12cm
Area of trapezium = 1/2 ×(sum of parallel sides) × (height)
= 1/2 × (10 + 20) × 12
= 180 sq.cm
Tags:
Maths