Question
Find the greatest number that will divide that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Medium
Solution
Verified by GMS
Given numbers are 43,91 and 183.
Subtract smallest number from both the highest numbers.
we have three cases :
183>43 ; 183>91 and 91>43
183−43=140
183−91=92 and
91−43=48
Now , we have three new numbers : 140,48 and 92
For HCF of 140,48 and 92 using prime factorization method, we get
HCF (140,48 and 92)=4
the highest number that divide 183,91 and 43 and leave the same remainder is 4.
Tags:
Maths