A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12ms −1. If the mass of the ball is 0.15 kg, determine the change in momentum of the ball.

The Impulse-momentum formula is obtained from the impulse-momentum theorem which states that change in momentum of an object is equal to impulse applied on the object. The formula is given as follows:

Impulse-momentum formula J=Δp

Solution

Given:
vi (Initial Velocity) = 12 m/s,

vf (Final Velocity) = -12m/s,

m (mass) = 0.15kg,

Find out

We have to determine the value of J (Impulse) = ?

Solution

Impulse is formulated as

J = mvf – mvi

= m(vf – vi)

On substituting the known values we get

= 0.15 Kg (-12 -12) m/s

J= -3.6N.