9303753286127016 Trigonometric Ratios of Complementary Angles

Trigonometric Ratios of Complementary Angles

Trigonometric Ratios of Complementary Angles

In Mathematics, the complementary angles are the set of two angles such that their sum is equal to 90°. For example, 30° and 60° are complementary to each other as their sum is equal to 90°. In this article, let us discuss in detail about the complementary angles and the trigonometric ratios of complementary angles with examples in a detailed way.



Complementary Angles Definition

The two angles, say ∠X and ∠Y are complementary if,

∠X + ∠Y = 90°

In such a condition ∠X is known as the complement of ∠Y and vice-versa.

In a right angle triangle, as the measure of the right angle is fixed, the remaining two angles always form the complementary as the sum of angles in a triangle is equal to 180°.

Finding Trigonometric Ratios of Complementary Angles

Assume a triangle ∆ABC, which is right-angled at B.

Complementary Angles

 

∠A and ∠C form a complementary pair.

⇒ ∠A + ∠C = 90°

The relationship between the acute angle and the lengths of sides of a right-angle triangle is expressed by trigonometric ratios. For the given right angle triangle, the  trigonometric ratios of ∠A is given as follows:

sin A = BC/AC

cos A = AB/AC

tan A =BC/AB

csc A = 1/sin A = AC/BC

sec A =1/cos A = AC/AB

cot A = 1/tan A = AB/BC

The trigonometric ratio of the complement of ∠A. It means that the ∠C can be given as 90° – ∠A

Complementary Angles

As ∠C = 90°- A (A is used for convenience instead of ∠A ), and the side opposite to 90° – A is AB and the side adjacent to the angle 90°- A is BC as shown in the figure given above.

Therefore,

sin (90°- A) = AB/AC

cos (90°- A) = BC/AC

tan (90°- A) = AB/BC

csc (90°- A) =1/sin (90°- A) = AC/AB

sec (90°- A) = 1/cos (90°- A) = AC/BC

cot (90°- A) = 1/tan (90°- A)  = BC/AB

Comparing the above set of ratios with the ratios mentioned earlier, it can be seen that;

sin (90°- A) = cos A ; cos (90°- A) = sin A

tan (90°- A) = cot A; cot (90°- A) = tan A

sec (90°- A) = csc A; csc (90°- A) = sec A

These relations are valid for all the values of A that lies between 0° and 90°.

Summary:

  • Sin of an angle = Cos of its complementary angle
  • Cos of an angle = Sin of its complementary angle
  • Tan of an angle = Cot of its complementary angle

Trigonometric Ratios of Complementary Angles Examples

To have a better insight on trigonometric ratios of complementary angles consider the following example.

Example:

If A, B and C are the interior angles of a right-angle triangle, right-angled at B then find the value of A, given that tan 2A = cot(A – 30°) and 2A is an acute angle.

Solution:

Using the trigonometric ratio of complementary angles,

cot (90°- A) = tan A

From this ratio, we can write the above expression as:

⇒ tan 2A = cot (90°- 2A) ….(1)

Given expression is tan 2A = cot (A – 30°) …(2)

Now, equate the equation (1) and (2), we get

cot (90°- 2A) = cot (A – 30°)

⇒ 90°- 2A = A – 30°

⇒3A = 90° + 30°

⇒3A = 120°

⇒A = 120°/ 3

⇒ A = 40°

Thus, the measure of the acute angle A can be easily calculated by making use of trigonometry ratio of complementary angles.

Balkishan Agrawal

At the helm of GMS Learning is Principal Balkishan Agrawal, a dedicated and experienced educationist. Under his able guidance, our school has flourished academically and has achieved remarkable milestones in various fields. Principal Agrawal’s vision for the school is centered on providing a nurturing environment where every student can thrive, learn, and grow.

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